Sarthaks Test
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Find the value of.

(i) (30 + 4−1) × 2

(ii) (2−1 × 4−1) ÷2−2

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(ii) (2−1 × 4−1) ÷ 2−2 

= [2−1 × {(2)2}− 1] ÷ 2− 2

= (2 −1 × 2− 2) ÷ 2− 2

= 2−1+ (−2) ÷ 2−2     (am × an = am + n)

= 2−3 ÷ 2−2

= 2−3 − (−2)             (am ÷ an = am − n)

= 2−3 + 2 = 2 −1

= 1/2                     

       

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