Question

The probability that a number selected at random from the numbers 1, 2, 3,...,15 is a multiple of 4, is

A. \(\frac{4}{15}\)

B. \(\frac{2}{15}\)

C. \(\frac{1}{5}\)

D.\(\frac{1}{3}\)

Answer 1

Total numbers of elementary events are: 15 

Let E be the event of getting a multiple of 4 

Favorable outcomes are: 4, 8, 12 

Numbers of favorable outcomes are = 3 

P (multiple of 4) = P (E) = \(\frac{3}{15}\) = \(\frac{1}{5}\)