∫ (cos2x - cos2θ)/(cosx - cosθ) dx is equal to : A. 2(sinx + x cosθ) + C B. 2(sinx – x cosθ) + C

Question

∫ (cos2x - cos2θ)/(cosx - cosθ) dx is equal to :

\(\int\frac{cos\,2x-cos\,2\theta}{cos\,x-cos\,\theta}\) dx =

A. 2(sinx + x cosθ) + C 

B. 2(sinx – x cosθ) + C 

C. 2(sinx + 2x cosθ) + C 

D. 2(sinx – 2x cosθ) + C

Answer 1

Option : (A)

Given,

∫ (cos2x - cos2θ)/(cosx - cosθ) dx