When two coins are tossed, total outcomes are
{HH, HT, TH, TT} = 4
A = Tail appears on one coin= {HT, TH} = 2
Probability of A = P(A) = \(\cfrac24=\cfrac12\)
B= One coin shows head ={HT, TH} = 2
Probability of B = P(B) = \(\cfrac24=\cfrac12\)
(A ∩ B) = one coin shows head and another shows tail = {HT, TH} = 2
P (A ∩ B) = \(\cfrac24=\cfrac12\)
Hence, \(P(\cfrac{A}{B})=\cfrac{P(A\cap B)}{P(B)}\)