Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
423 views
in Linear Programming by (47.5k points)
closed by

A manufacturer of patent medicines is preparing a production plan on medicines, A and B. There are sufficient raw materials available to make 20000 bottles of A and 40000 bottles of B, but there are only 45000 bottles into which either of the medicines can be put. Further, it takes 3 hours to prepare enough material to fill 1000 bottles of A, it takes 1 hours to prepare enough material to fill 1000 bottles of B and there are 66 hours available for this operation. The profit is Rs. 8 per bottle for A and Rs 7 per bottle for B. How should the manufacturer schedule his production in order to maximize his profit?

1 Answer

+1 vote
by (45.1k points)
selected by
 
Best answer

Let production of each bottle of A and B are x and y respectively.

Since profits on each bottle of A and B are Rs 8 and Rs 7 per bottle respectively. So, profit on x bottles of A and y bottles of of B are 8x and 7y respectively. Let Z be total profit on bottles so,

Z = 8x + 7y

Since, it takes 3 hours and 1 hour to prepare enough material to fill 1000 bottles of Type A and Type B respectively, so x bottles of A and y bottles of B are preparing is \(\frac{3x}{1000}\) hours and \(\frac{y}{1000}\) hours respectively, bout only 66 hours are available, so,

Since raw materials available to make 2000 bottles of A and 4000 bottles of B but there are 45000 bottles in which either of these medicines can be put so,

[Since production of bottles can not be negative]

Hence mathematical formulation of the given LPP is,

Max Z = 8x + 7y

Subject to constraints,

Region 3x + y ≤ 66000: line 3x + y = 66000 meets the axes at A(22000, 0), B(0, 66000) respectively.

Region containing origin represents 3x + y ≤ 10000 as (0, 0) satisfy 3x + y ≤ 66000

Region x + y ≤ 45000: line x + y = 45000 meets the axes at C(45000, 0), D(0, 45000) respectively.

Region towards the origin will satisfy the inequation as (0,00 satisfies the inequation)

Region represented by x ≤ 20000,

x = 20000 is the line passes through (20000, 0) and is parallel to the Y - axis. The region towards the origin will satisfy the inequation.

Region represented by y ≤ 40000,

y = 40000 is the line passes through (0, 40000) and is parallel to the X - axis. The region towards the origin will satisfy the inequation.

Region x, y ≥ 0: it represents first quadrant.

The corner points are O(0, 0), B(0, 40000), G(10500, 34500), H(20000, 6000), A(20000, 0).

The values of Z at these corner points are,

The maximum value of Z is 325500 which is attained at G(10500, 34500).

Thus the maximum profit is Rs 325500 obtained when 10500 bottles of A and 34500 bottles of B are manufactured.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...