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0 votes
4.7k views
in Linear Programming by (45.0k points)
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The region represented by the inequation system x, y ≥ 0, y ≤ 6, x + y ≤ 3 is

A. Unbounded in first quadrant

B. Unbounded in first and second quadrants

C. Bounded in first quadrant

D. None of these

1 Answer

+1 vote
by (47.4k points)
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Best answer

Correct answer is A.

Given inequations are

x, y ≥ 0, y ≤ 6, x + y ≤ 3

If we graph the inequalities y ≤ 6 and x + y ≤ 3 on the graph, we get the graph,

Here we can clearly see that, the region for the inequality is above the points A, B, C and D. But considering the constraints x , y ≥ 0, this clearly shows that the region can only be in the 1st quadrant.

So from the green color highlighted area, we can say that, the region of the inequalities is unbound in the first quadrant.

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