Correct option is A. 1/36
Probability of getting blue face is .\(\cfrac16\)
Probability of getting yellow face is \(\cfrac36\).
Probability of getting red face is \(\cfrac26\).
probability that yellow red and blue face appear in the first second and third throws is
P = \(\cfrac36\times\cfrac26\times\cfrac16\) = \(\cfrac{1}{36}\)