Sarthaks Test
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In the below fig, arms BA and BC of ∠ABC are respectively parallel to arms ED and EF of ∠DEF. Prove that ∠ABC = ∠DEF.

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Given AB || DE and BC || EF

To prove: ABC = DEF 

Construction: Produce BC to x such that it intersects DE at M. 

Proof: Since AB || DE and BX is the transversal

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