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In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and T, 8 read both T and I, 3 read all three newspapers. Find:  the numbers of people who read at least one of the newspapers

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Total number of People n(P) = 60. 

n(H) =25. 

n(T) = 26. 

n(I) = 26. 

n (H ∩ I) = 9 

n (H ∩ T) = 11 

n (T ∩ I) = 8 

n (H ∩T ∩ I) = 3 

The people who read at least one newspaper would be n(H or I or T) = n(H∪I∪T) 

We know, 

n(H∪I∪T) = n(H)+n(I)+n(T) – n (H ∩ I)– n (H ∩ T)– n (T ∩ I)+ n (H ∩T ∩ I) 

n(H∪I∪T) = 25+26+26–9–11–8+3 

n(H∪I∪T) = 52. 

There are 52 people who read at least one newspaper.

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