(a) F - (500 ×10) = (500 × 15) or F = 12.5 × 103 N, where F is the upward reaction of the floor and is equal to the force downwards on the floor, by Newton’s 3rd law of motion
(b) R - (2500 × 10) = (2500 × 15) or R = 6.25 × 104 N, action of the air on the system, upwards. The action of the rotor on the surrounding air is 6.25 × 104 N downwards.
(c) Force on the helicopter due to the air = 6.25 × 104 N upwards