Sarthaks Test
0 votes
99 views
in Mathematics by (35.6k points)
Find the area of a quadrilateral ABCD is which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

1 Answer

0 votes
by (61.7k points)
selected by
 
Best answer

For ∆PQR

PQ= QR2 + RP2

(52) = (3)2 + (4)2 [∵ PR = 3 QR = 4 and PQ = 5] 

So, ∆PQR is a right angled triangle. Right angle at point R.

Perimeter = 2s = AC + CD + DA = (5 + 4 + 5)cm = 14 cm 

S = 7 cm 

By Heron’s formula

Area of PQRS = Area of PQR + Area of ∆PQS = (6 + 9.166) cm2 = 15.166 cm2.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...