1. (a) 5x-4y = 40
5x - 8y = -80
Let the Number of children = x
Amount distributed by Seema for one child = Rs y
Now,
Total money = xy
And, Total money will remain the same
Given that
If there were 8 children less, everyone would have got Rs. 10 more.
Total money now = Total money before
5x - 4y = 40 ...(1)
Also
if there were 16 children more, everyone would have got Rs. 10 less
Total money now = Total money before
Dividing both sides by 2
5x - 8y = -80 ...(2)
Thus, the equations are
5x - 4y = 40
5x - 8y = -80
2. (c)
Since the equation are
5x - 4y = 40
5x - 8y = -80
We write it as
3. (d) 32
We need to find x
The equation is
5x - 4y = 40 ----(1)
5x - 8y = -80 ---(2)
Subtracting (1) and (2)
Putting y = 30 in (1)
Thus,
Number of children = x = 32
4. (b) Rs.30
Amount given to each child = Rs y
= Rs 30
5. (b) Rs.960
Total Amount = Number of students x Money spent per student
= xy
= 32 × 30
= Rs 960