Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
796 views
in Matrices by (29.8k points)
closed by

On her birth day, Seema decided to donate some money to children of an orphanage home. If there were 8 children less, everyone would have got Rs.10 more. However, if there were 16 children more, everyone would have got Rs. 10 less. Let the number of children be x and the amount distributed by Seema for one child be y (in Rs.).

Based on the information given above, answer the following questions:

1. The equations in terms x and y ar

a. 5x - 4y = 40

     5x -8y = -80

b. 5x - 4y = 40

     5x - 8y = 80

c. 5x - 4y = 40

    5x + 8y = -80

d. 5x + 4y = 40

     5x - 8y = -80

2. Which of the following matrix equations represent the information given above?

3. The number of children who were given some money by Seema, is

a. 30

b. 40

c. 23

d. 32

4. How much amount is given to each child by Seema?

a. Rs. 32

b. Rs. 30

c. Rs. 62

d. Rs. 26

5. How much amount Seema spends in distributing the money to all the students of the Orphanage?

a. Rs. 609

b. Rs. 960

c. Rs. 906

d. Rs. 690

2 Answers

+1 vote
by (46.5k points)
selected by
 
Best answer

1. (a) 5x-4y = 40

5x - 8y = -80

Let the Number of children = x

Amount distributed by Seema for one child = Rs y

Now,

Total money = xy

And, Total money will remain the same

Given that

If there were 8 children less, everyone would have got Rs. 10 more.

Total money now = Total money before

5x - 4y = 40 ...(1)

Also

if there were 16 children more, everyone would have got Rs. 10 less

Total money now = Total money before

Dividing both sides by 2

5x - 8y = -80 ...(2)

Thus, the equations are

5x - 4y = 40

5x - 8y = -80

2. (c)

Since the equation are

5x - 4y = 40

5x - 8y = -80

We write it as

3. (d) 32

We need to find x

The equation is 

5x - 4y = 40 ----(1)

5x - 8y = -80 ---(2)

Subtracting (1) and (2)

Putting y = 30 in (1)

Thus,

Number of children = x = 32

4. (b) Rs.30

Amount given to each child = Rs y 

= Rs 30

5. (b) Rs.960

Total Amount = Number of students x Money spent per student

= xy

= 32 × 30

= Rs 960

+2 votes
by (28.9k points)

1. (a) 5x-4y = 40

      5x - 8y = -80

3. (d) 32

4. (b) Rs.30

5. (b) Rs.960

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...