Sarthaks Test
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The sides of a quadrilateral, taken in order are 5, 12, 14 and 15 meters respectively, and the angle contained by the first two sides is a right angle. Find its area.

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Given that sides of quadrilateral are AB = 5 m, BC = 12 m, CD = 14 m and DA = 15 m AB = 5m, BC = 12m, CD = 14 m and DA = 15 m 

Join AC

In ∆ABC By applying Pythagoras theorem.

By using Heron’s formula

Area of quadrilateral ABCD = area of ( ∆ABC) + Area of (∆ADC) = 30+84 = 114 m2

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