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+2 votes
87.7k views
in Arithmetic Progression by (29.9k points)
closed by

Your elder brother wants to buy a car and plans to take loan from a bank for his car. He repays his total loan of Rs 1,18,000 by paying every month starting with the first instalment of Rs 1000. If he increases the instalment by Rs 100 every month , answer the following:

1. The amount paid by him in 30th installment is

a) 3900

b) 3500

c) 3700

d) 3600

2. The amount paid by him in the 30 installments is

a) 37000

b) 73500

c) 75300

d) 75000

3. What amount does he still have to pay offer 30th installment?

a) 45500

b) 49000

c) 44500

d) 54000

4. If total installments are 40 then amount paid in the last installment?

a) 4900

b) 3900

c) 5900

d) 9400

5. The ratio of the 1st installment to the last installment is

a) 1:49

b) 10:49

c) 10:39

d) 39:10

3 Answers

+1 vote
by (17.0k points)
selected by
 
Best answer

l = 1,18,000

a = 1000

d = 100

1. a30 = a + 29d

= 1000 + 29(100)

= 1000 + 2900

= 3900

2. Amount paid by him in the 30 installments = 30/2 [2000 + 2900]

= 15[2000 + 2900]

= 30000 + 43500

= 73500

3. Money remaining to pay after the 30th payment = 118000 - 73500

= 44500

4. a40 = 1000 + 39(100)

= 1000 + 3900

= 4900

5. a = 1000

a40 = 4900

= 1000 : 4900

= 10 : 49

+2 votes
by (29.0k points)

1. a) 3900

2. b) 73500

3. c) 44500

4. a) 4900

5. b) 10 : 49

+3 votes
by (30 points)
Q1
image

Q2
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sorry i didn't understand Q3

Q4
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Q5
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by (10 points)
Q3. Answer
118000-73500=44500
According to the question
Money remaining to pay after the 30th payment
That is why 44500

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