Question

A cricket fielder can throw the cricket ball with a speed v_o. If he throws the ball while running with speed u at an angle θ to the horizontal, find

(a) the effective angle to the horizontal at which the ball is projected in air as seen by a spectator.

(b) what will be time of flight?

(c) what is the distance (horizontal range) from the point of projection at which the ball will land?

(d) find θ at which he should throw the ball that would maximise the horizontal range as found in (iii).

(e) how does θ for maximum range change if u >v_o , u = v_o , u < v_o ?

(f) how does θ in (v) compare with that for u = 0 (i.e.45^o)?

Answer 1

find the effective angle to the horizontal at which the ball is projected in air as seen by a spectator.

Answer 2

The observer on ground (spectator) observes that the x-component of ball is more because of the speed of fielder. As shown in the adjacent diagram, 

So, initial velocity in x-direction .