Question

Rahul and Ravi planned to play Business ( board game) in which they were supposed to use two dice.

1. Ravi got first chance to roll the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 8?

2. Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 13?

3. Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is less than or equal to 12 ?

4. Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is equal to 7 ?

5. Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is greater than 8 ?

Answer 1

1. b) 5/36

Number of outcomes where sum is 8 = 5

Probability that sum of two numbers is 8

= Number of outcomes where sum is 8 / Total number of outcomes

= 5/36

2. d) 0

Number of outcomes where sum is 13 = 0

Probability that sum of two numbers is 13

= Number of outcomes where sum is 13 / Total number of outcomes

= 0/36

= 0

3. a) 1

Number of outcomes where sum is less than or equal to 12 = 36

Probability that sum of two numbers is less than or equal to 12

= Number of outcomes where sum is less than or equal to 12 / Total number of outcomes

= 36/36

= 1

4. c) 1/6

Number of outcomes where sum is 7 = 6

Probability that sum of two numbers is 7

= Number of outcomes where sum is 7 / Total number of outcomes

= 6/36

= 1/6

5. d) 5/18

Number of outcomes where sum is greater than 8

= 4 + 3 + 2 + 1

= 10

Probability that sum of two numbers is greater than 8

= Number of outcomes where sum is greater than 8 / Total number of outcomes

= 10/36

= 5/18

Answer 2

1. b) \(\cfrac5{36}\)

2. d) 0

3. a) 1

4. c) \(\cfrac16\)

5. d) \(\cfrac{5}{18}\)