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in Trigonometry by (45.0k points)
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\(\frac{\text{sin 3x}}{\text{1 + 2 cos 2x}}\) is equal to

A. cos x

B. sin x

C. - cos x

D. sin x

1 Answer

+1 vote
by (47.4k points)
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Best answer

Correct answer is B.

Given expression \(\frac{\text{sin 3x}}{\text{1 + 2 cos 2x}}\)

[Using the formulae sin 3x = 3sinx – 4sin3x and cos2x = 1 – 2sin2x]

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