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The value of (2(sin 2x + 2 cos^2 x - 1))/(cos x - sin x - cos 3x + sin 3x)

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The value of \(\frac{2\left(\text{sin 2x} + 2\text{cos}^2 x-1\right)}{\text{cos x - sin x - cos 3x + sin 3x}}\) is

A. cos x

B. sec x

C. cosec x

D. sin x

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Correct answer is C.

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