A die is thrown once.
Therefore, possible outcomes are {1, 2, 3, 4, 5, 6}.
Hence, total possible outcomes = n(S) = 6.
Let the event E be the event of getting an even prime number.
Since, only even prime number is 2.
Therefore, number of outcomes favourable to event E is n(E) = 1
Hence, the probability of getting an even prime number = \(\frac{n(E)}{n(s)} = \frac{1}{6}\)
