Let a, b ∈ Z, where Z is set of integers.
Given binary operation is a ∗ b = ab3 .
Now, b ∗ a = ba3 ≠ ab3 = a ∗ b. ( \(\because\) ba3 ≠ ab3 , where a and b are arbitrary integers )
Therefore, b ∗ a ≠ a ∗ b.
Therefore, the binary operation ‘∗’ is not commutative.