∫1/(sin x - sin 2x) dx
=\(\int\cfrac{1}{sin\,x-sin\,2x}dx\) = \(\int\cfrac{1}{sin\,x-2sin\,x\,cos\,x}dx\) (\(\because\) sin 2x = 2sin x cosx)
(\(\because\) sin2x = 2 sin x cos x)
Where, C is an integral constant. Now, putting t = cos x, we get
Where C is an integral constant.