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Calculate the number of electrons constituting 1C of charge?

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We have, q = ne, where q = charge

∴ n = \(\frac{q}{e}\)  e = charge on an electron and n = number of electrons

\(\frac{1}{1.6\times10^{-19}}\) 

= 6.25 x 1018 

= 6 x 1018 electrons.

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