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in Mathematics by (11.0k points)

(a) Write a positive integer and a negative integer whose sum is a negative integer.

(b) Write a positive integer and a negative integer whose sum is a  positive integer.

(c) Write a positive integer and a negative integer whose difference is a negative integer.

(d) Write a positive integer and a negative integer whose difference is a positive integer.

(e) Write two integers which are smaller than – 5 but their difference is – 5.

(f) Write two integers which are greater than – 10 but their sum is smaller than – 10.

(g) Write two integers which are greater than – 4 but their difference is smaller than – 4.

(h) Write two integers which are smaller than – 6 but their difference is greater than – 6.

(i) Write two negative integers whose difference is 7.

(j) Write two integers such that one is smaller than –11, and other

is greater than –11 but their difference is –11.

(k) Write two integers whose product is smaller than both the integers.

(l) Write two integers whose product is greater than both the integers.

1 Answer

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(a) A number of solutions can be possible e.g., 4 + (–6) = –2 

(b) A number of solutions can be possible e.g., 8 + (–2) = 6 

(c) A number of solutions can be possible e.g., –7 – (2) = –9 

(d) A number of solutions can be possible e.g., 4 – (–3) = 7 

(e) A number of solutions can be possible e.g., –12 – (–7) = –5 

(f) A number of solutions can be possible e.g., –4 + (–7) = –11 < –10 

(g) A number of solutions can be possible e.g., –1 – 4 = –5 < –4 (

h) A number of solutions can be possible e.g., –8 – (–9) = 1 > –6 

(i) A number of solutions can be possible e.g., –2 – (–10) = 8 

(j) A number of solutions can be possible e.g., –20 – (–9) = –11 

(k) A number of solutions can be possible e.g., –3 × 5 = –15 

(l) A number of solutions can be possible e.g., 4 × 6 = 24.

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