Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
423 views
in Mathematical Induction by (32.3k points)
closed by

Given a1 = \(\frac{1}2(a_0+\frac{A}{a_0}),a_2\) = \(\frac{1}2(a_1+\frac{A}{a_1})\) and an+1 \(\frac{1}2(a_n+\frac{A}{a_n})\) for n ≥ 2, where a > 0, A > 0

1 Answer

+1 vote
by (32.2k points)
selected by
 
Best answer

Given, a1 = \(\frac{1}2(a_0+\frac{A}{a_0}),a_2\) = \(\frac{1}2(a_1+\frac{A}{a_1})\) and an+1\(\frac{1}2(a_n+\frac{A}{a_n})\),a,A>0

Step1: For n = 1

As LHS = RHS. 

So, it is true for P(1) 

For n = k, let P(k) be true.

Now, we need to show P(k+1) is true whenever P(k) is true. 

P(k+1):

As L.H.S = R.H.S 

Thus, P(k+1) is true. So, by the principle of mathematical induction 

P(n) is true for all n.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...