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If a = cos θ + i sin θ, find the value of \(\frac{1+a}{1-a}\)

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Given: ⇒ a=cosθ+isinθ

⇒ \(\frac{1+a}{1-a}\) = \(\frac{1+cosθ+isinθ}{1-cosθ-isinθ}\) 

We know that 1+cos2θ=2cos 2θ, 1-cos2θ=2sin 2θ and sin2θ=2sinθcosθ

We know that i2=-1

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