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in Chemical Kinetics by (20 points)
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The rate of formation not a dimer in a second order reaction is 7.5*10-3 mol ls at 0.05 mol l monomer concentration. Calculate the rate constant?

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1 Answer

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by (24.8k points)

Let us consider the dimensation of a monomer M

2M → (M)2

Rate = k [M]n 

Given that n =2 and [M] = 0.05 mol L-1

Rate = 7.5 x 10-3 mol L-1 s-1

Rate 7.5 x 103 mol L-1 s-1

k = \(\frac{Rate}{[M]^n}\)

k = \(\frac{7.5\times10^{-3}}{(0.05)^2}\) 

= 3 mol-1 Ls-1

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