Let us consider the dimensation of a monomer M
2M → (M)2
Rate = k [M]n
Given that n =2 and [M] = 0.05 mol L-1
Rate = 7.5 x 10-3 mol L-1 s-1
Rate 7.5 x 103 mol L-1 s-1
k = \(\frac{Rate}{[M]^n}\)
k = \(\frac{7.5\times10^{-3}}{(0.05)^2}\)
= 3 mol-1 Ls-1