The coordinates of a centroid of a triangle whose vertices are (x1, y1), (x2, y2) & (x3, y3) is given by \((\frac{x_1+x_2+x_3}3,\frac{y_1+y_2+y_3}3)\)
Given that A(–1, 0), B(5, –2) and C(8, 2) are the vertices of a triangle ∆ABC.
Then, the co-ordinates of the centroid is \((\frac{-1+5+8}3,\frac{0-2+2}3)\) = \((\frac{12}3,\frac{0}3)\) = (4,0).
Hence, the coordinates of the centroid of triangle ∆ABC is (4, 0).