Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
378 views
in Exponents by (30.8k points)
closed by

Thickness of a paper = 0.03 mm. Express it in standard form.

1 Answer

+1 vote
by (24.8k points)
selected by
 
Best answer

Given Thickness of paper =0.03 mm 

But we know that 0.03= 3/100 ​ 

But according to the law we have a −m =(1/am

Using this in above equation we get size of bacteria =0.03 mm=3×10 −2 mm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...