x + iy)1/3 = a + ib
x + iy = (a + ib)3
= a3 + (ib)3 + 3a2(ib) + 3a(ib)2
= a3 – ib3 + i3a2b – 3ab2
= (a3 – 3ab2) + i(3a2b – b3)
x = a3 – 3ab2 and y = 3a2b – b3
\(\frac{x}{a}+\frac{y}{b}\) = \(\frac{a^3-3ab^2}{a}+\frac{3a^2b-b^3}{b}\)
= a3 – 3b2 + 3a2 – b3
= 4(a2 – b2)