# If the complex number z = x + iy satisfies the condition |z + 1| = 1, then z lies on

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If the complex number z = x + iy satisfies the condition |z + 1| = 1, then z lies on

A. x-axis

B. circle with centre (-1, 0) and radius 1

C. y-axis

D. None of these

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|z + 1| = 1

|x + iy + 1| = 1

|(1 + x) + iy| = 1

$\sqrt{(1+x)^2 + y^2} =1$

(x + 1)2 + y= 1

(x – (-1))2 + (y – 0)2 = (1)

So, we can say that it is a circle with centre (-1,0) and radius 1