Question

Evaluate

(i) 3^-4

(ii) (-4)³

(iii) (3/4)^-2

(iv) (5/7)⁰

Answer 1

(i) 3^-4 \(=\frac{1}{3^4}=\frac{1}{81}\)

(ii) (-4)³ = (-1)³ × (4)³ = -1 × 64 = -64

(iii) \((\frac{3}{4})^{-2}=(\frac{4}{3})^2=\frac{4^2}{3^3}=\frac{16}{9}\)

(v) Using the property \((\frac{a}{b})^0=1\) we will get,

\((\frac{5}{7})^0=1\)