Sarthaks Test
+2 votes
138 views
in JEE by (498 points)

The figure shows a conductor of weight 1N and length L=0.5m placed on a rough inclined plane making an angle 30° with the horizontal so that conductor is perpendicular to a uniform horizontal magnetic field of induction B = 0.10T. The coefficient of static friction between the conductor and the plane is 0.10. A current of I = 10A flows through the conductor inside the plane of this paper as shown. What is the force needed to be applied parallel to the inclined plane to sustain the conductor at rest ? 

1 Answer

+1 vote
by (64.6k points)
selected by
 
Best answer

Force needed to be applied parallel to the inclined plane to sustain the conductor at rest is 0.62 N < F < 0.88 N

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...