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in Mathematics by (15.9k points)

Show that the points whose position vectors are 5\(\hat i\)+ 6\(\hat j\)+ 7\(\hat k\), 7\(\hat i\)− 8\(\hat j\)+ 9\(\hat k\) and 3\(\hat i\)+ 20\(\hat j\)+ 5\(\hat k\) are collinear.

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Given that the position vector of points , and are 5\(\hat i\)+ 6\(\hat j\)+ 7\(\hat k\), 7\(\hat i\)− 8\(\hat j\)+ 9\(\hat k\) and 3\(\hat i\)+ 20\(\hat j\)+ 5\(\hat k\), respectively.

Hence, the points , and are collinear. 

Hence, the points whose position vectors are ( 5\(\hat i\)+ 6\(\hat j\)+ 7\(\hat k\), ), ( 7\(\hat i\)− 8\(\hat j\)+ 9\(\hat k\) ) and 3\(\hat i\)+ 20\(\hat j\)+ 5\(\hat k\)  are collinear.

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