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A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. The initial velocity of the shell is

(a) 40 ms−1

(b) 120 ms−1

(c) 100 ms−1

(d) 10 ms−1

1 Answer

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Best answer

Correct option is : (c) 100 ms−1

Total energy = E1 + E2 = 1050 J

As, E \(=\frac{p^2}{2m}\Rightarrow \frac{E_1}{E_2}=\frac{m_2}{m_1}=\frac{4}{0.2}\) = 20.

where, m1 = mass of shell

and m2 = mass of gun.

\(\Rightarrow E_2=\frac{E_1}{20}\)

\(\Rightarrow E_1+\frac{E_1}{20}\) = 1050

⇒ E1 = 1000 J

 KE = \(\frac{1}{2}m_1v^2_1=1000\)

⇒ v1\(\sqrt{10000}\) = 100 ms-1

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