Correct option is : (c) 100 ms−1
Total energy = E1 + E2 = 1050 J
As, E \(=\frac{p^2}{2m}\Rightarrow \frac{E_1}{E_2}=\frac{m_2}{m_1}=\frac{4}{0.2}\) = 20.
where, m1 = mass of shell
and m2 = mass of gun.
\(\Rightarrow E_2=\frac{E_1}{20}\)
\(\Rightarrow E_1+\frac{E_1}{20}\) = 1050
⇒ E1 = 1000 J
∴ KE = \(\frac{1}{2}m_1v^2_1=1000\)
⇒ v1 = \(\sqrt{10000}\) = 100 ms-1