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in Oscillations and waves by (30 points)
edited by

S1: The particle speed can never be equal to the wave speed in sine wave if the amplitude is less than wavelength divided by 2π

S2: In a transverse wave of amplitude A, the maximum particle velocity is four times its wave velocity. Then the wavelength of the wave is πA

S3: The phase difference between two points separated by 1 m in a wave of frequency 120 Hz is 90°. The velocity of the wave is 480 m/s

A) FTT

B) TTF 

C) TFT

D) FFF

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1 Answer

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by (29.6k points)

The correct option is (C) TFT

S1: True

S2: False

Amplitude of the wave = A

Maximum velocity of wave

vmax = 4v (where v is the wave velocity)

The relation for the maximum velocity is

vmax = 4ω

4v = 4ω 

ω = 4v/A

Wavelength of the wave is given by

Where f is the frequency f = ω/2π from ω = 2πf

S3: True

Distance between two points Δx = 1m frequency n = 120Hz

Phase difference ϕ = 90= 0.5π

The relation for the phase difference is

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