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in Number System by (30.8k points)
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Replace A, B, C by suitable numerals.

\(\begin{equation} \frac{ \begin{array}[b]{r} 5&A\\ +\,\,\,8&7 \end{array} }{ C\,\,B\,\,\,3 } \end{equation}\)

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Best answer

Here, in units place,

A + 7 = 3

Ie, A = -4, which is not possible.

Hence A is greater than 10,where, 1 carry is given to tens place.

∴ A + 7 = 13

∴ A = 6

Now in tens place,

5 + 8 + 1 = B …as 1 is carried

∴ B = 14

Here, 1 will be carried to hundreds place. 

Hence, B = 4 and C = 1

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