Question

If α, β, γ be the zeroes of the polynomial x³ – 6x² – x + 30, then (αβ + βγ + γα) = ? 

(a) -1 

(b) 1 

(c) -5 

(d) 30

Answer 1

(a) -1 

It is given that α, β and γ are the zeroes of x³ – 6x² – x + 30.

∴ (αβ + βγ + γα) = \(\frac{coefficient\,of\,x}{coefficient\,of\,x^3}\) = \(\frac{-1}1\) = - 1