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in Polynomials by (32.2k points)
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If one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is 0, then the product of the other two zeroes is

(a) \(\frac{-c}a\)

(b) \(\frac{c}a\)

(c)

(d) \(\frac{-b}a\)

1 Answer

+2 votes
by (32.1k points)
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Best answer

(b) \(\frac{c}a\)

Let α, β and 0 be the zeroes of ax3 + bx2 + cx + d. 

Then, sum of the products of zeroes taking two at a time is given by 

(αβ + β × 0 + α × 0) = \(\frac{c}a\) 

⇒ αβ = \(\frac{c}a\) 

∴ The product of the other two zeroes is \(\frac{c}a\).

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