Question

If α, β, γ be the zeroes of the polynomial x³ – 6x² – x + 3, then the values of (αβ + βγ + γα) = ? 

(a) -1 

(b) 1 

(c) -5 

(d) 3

Answer 1

(a) -1 

Here, 

p(x) = x³ – 6x² – x + 3 

Comparing the given polynomial with x³ – (α + β + γ) x² + (αβ + βγ + γα) x – αβγ, 

we get:

(αβ + βγ + γα) = -1