p(x) = x3 – 6x2 + 11x – 6 and its factor, x + 3
Let us divide p(x) by (x – 3).
Here, x3 – 6x2 + 11x – 6 = (x – 3) (x2 – 3x + 2)
= (x – 3) [(x2 – (2 + 1) x + 2]
= (x – 3) (x2 – 2x – x + 2)
= (x – 3) [x (x – 2) – 1(x – 2)]
= (x – 3) (x – 1) (x – 2)
∴The other two zeroes are 1 and 2.