Question

In Fig. 10.24, AB = AC and ∠ACD =105°, find ∠BAC.

Fig.10.24

Answer 1

Consider the given figure

We have,

AB = AC and ∠ACD =105°

And also,

ΔABC is an isosceles triangle [AB=AC]

⇒∠ABC=∠ACB  [Angles opposite to equal sides are equal]

From (1), we have