(i) Given,
(x – 4)(x – 4)
By using the formula (a – b)2 = a2 – 2ab + b2
We get;
= (x – 4)2
= (x)2 – 2 × (x) × 4 + (4)2
= x2 – 8x + 16
(ii) Given,
(2x – 3y)(2x – 3y)
By using the formula (a – b)2 = a2 – 2ab + b2
We get;
= (2x – 3y)2
= (2x)2 – 2 × (2x) × (3y) + (3y)2
= 4x2 – 12xy + 9y2
(iii) \((\frac{3}{4}\text{x} - \frac{5}{6}y)(\frac{3}{4}\text{x}-\frac{5}{6}y)\)
By using the formula (a – b)2 = a2 – 2ab + b2
We get;
(iv) \((\text{x}-\frac{3}{\text{x}})(\text{x}-\frac{3}{\text{x}})\)
By using the formula (a – b)2 = a2 – 2ab + b2
We get;
(v) \((\frac{1}{3}\text{x}^2-9)(\frac{1}{3}\text{x}^{2}-9)\)
By using the formula (a – b)2 = a2 – 2ab + b2
We get;
(vi) \((\frac{1}{2}y^2-\frac{1}{3}y)(\frac{1}{2}y^2-\frac{1}{3}y)\)