Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
234 views
in Algebraic Expressions by (31.2k points)
closed by

Find each of the following products:

(i) (x + 3)(x – 3) 

(ii) (2x + 5)(2x – 5) 

(iii) (8 + x)(8 – x) 

(iv) (7x + 11y)(7x – 11y)

1 Answer

+1 vote
by (30.8k points)
selected by
 
Best answer

(i) Given, 

(x + 3)(x – 3) 

By using the formula (a + b) (a – b) = a2 – b

We get; 

= x(x + 3) – 3(x + 3) 

= x2 + 3x – 3x – 9 

= x2 – 9

(ii) Given, 

(2x + 5)(2x – 5) 

By using the formula (a + b) (a – b) = a2 – b2 

We get; 

= 2x(2x + 5) – 5(2x + 5) 

= 4x2 + 10x – 10x – 25 

= 4x2 – 25

(iii) Given, 

(8 + x)(8 – x) 

By using the formula (a + b) (a – b) = a2 – b2 

We get; 

= 8(8 + x) – x(8 + x) 

= 64 + 8x – 8x – x

= 64 – x2

(iv) Given, 

(7x + 11y)(7x – 11y) 

By using the formula (a + b) (a – b) = a2 – b2 

We get; 

= 7x(7x + 11y) – 11y(7x + 11y) 

= 49x2 + 77xy – 77xy – 121y2 

= 49x2 – 121y2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...