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in Algebraic Expressions by (31.2k points)
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Find the value of the expression (64x2 + 81y2 + 144xy), when x = 11 and y = \(\frac{4}{3}\,.\)

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Best answer

Given,

(64x2 + 81y2 + 144xy)

X = 11

Y = \(\frac{4}{3}\)

By using the formula (a + b)2 we get;

= (8x)2 + (9y)2 + 2(8x)(9y)

= (8x + 9y)2

= [8(11) + 9 \((\frac{4}{3})]^2\)

= (88 + 12)2

= (100)2 = 10000

Hence the value of the expression is 10000.

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