Question

The sum of (6a + 4b – c + 3), (2b – 3c + 4), (11b – 7a + 2c - 1) and (2c – 5a - 6) is

A. (4a - 6b + 2)

B. (-3a + 14b - 3c + 2)

C. (-6a + 17b)

D. (-6a + 6b + c - 4)

Answer 1

\(\begin{equation} \frac{ \begin{array}[b]{r} 6a\,+\,4b\,-c\,+\,3\\ +2b\,-3c\,+\,4\\ -7a\,+\,11b\,+2c\,-\,1\\ -5a \,\,\,\,\,+2c-6 \end{array} }{ -6a\,\,+17b } \end{equation}\)