(i) Let’s find out the HCF of 14x3, 21x4y and 28x2y2
7x2 is the highest common factor of 14x3, 21x4y,28x2y2
So,
14x3 + 21x4y – 28x2y2 = 7x2(2x + 3x2y – 4y2)
5 is the highest common factor of 5, 10t and 20t2.
So,
- 5 – 10t + 20t2 = - 5(1 + 2t – 4t2)
(Note: As we have learned in the previous chapter when we multiplied – sign with – sign it become +)