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in Factorization by (30.8k points)
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Factories: 

6ab – b2 + 12ac – 2bc

1 Answer

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Best answer

6ab – b2 + 12ac – 2bc 

= 6ab + 12ac – b2 – 2bc 

= (6ab + 12ac) – (b2 + 2bc) 

= 6a(b + 2c) – b(b + 2c) 

= (b + 2c)(6a – b) 

So we get, 

6ab – b2 + 12ac – 2bc = (b + 2c)(6a – b)

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