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in Factorization by (30.8k points)
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1 – 2ab – (a2 + b2) =? 

A. (1 + a - b) (1 + a + b) 

B. (1 + a + b) (1 - a + b) 

C. (1 + a + b) (1 - a - b) 

D. (1 + a - b) (1 - a + b)

1 Answer

+1 vote
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Best answer

1 – 2ab – (a2 + b2) = 1 – 2ab – a2 – b2 

= 1 – (2ab + a2 + b2

= 1 – (a + b)2 

= (1 – a – b)(1 + a + b) \(\because\) a2 – b2 = (a – b)(a + b)

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