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y^2 + 2y – 3=?  A. (y - 1) (y + 3)  B. (y + 1) (y - 3)  C. (y - 1) (y - 3)  D. (y + 2) (y - 3)

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y2 + 2y – 3=? 

A. (y - 1) (y + 3) 

B. (y + 1) (y - 3) 

C. (y - 1) (y - 3) 

D. (y + 2) (y - 3)

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1 Answer

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Best answer

y2 + 2y – 3 

Factorizing the equation and taking y and – 1 as common, 

= y2 + 3y – y – 3 

= y(y + 3) – 1(y + 3) 

= (y + 3)(y – 1).

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