Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
514 views
in Factorization by (31.2k points)
closed by

4z2 – 8z + 3=? 

A. (2z – 1) (2z – 3) 

B. (2z + 1) (3 – 2z) 

C. (2z + 3) (3z + 1) 

D. (z – 1) (4z – 3)

1 Answer

+1 vote
by (30.8k points)
selected by
 
Best answer

4z2 – 8z + 3 

Factorizing the equation and taking 2z and – 1 as common, 

= 4z2 – 6z – 2z + 3 

= 2z(2z – 3) – 1(2z – 3) 

= (2z – 1)(2z – 3).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...